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Nexa's Sense of SnowFollow

#27 Mar 01 2008 at 1:34 PM Rating: Decent
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Flip a switch. no more shoveling!


Just a $1000 a month heating bill.

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#28 Mar 01 2008 at 2:32 PM Rating: Good
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Can't you just throw some boiled lobsters on the driveway?
#29 Mar 01 2008 at 3:10 PM Rating: Decent
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Move. Duh.
#30 Mar 01 2008 at 11:36 PM Rating: Excellent
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Smasharoo wrote:


Just a $1000 a month heating bill.



Nah, The systems they have commercially add maybe $20 per month to the electrical bill during the winter, but i'd say thats worth it. you just have to raise it slightly above ambient.
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#31 Mar 04 2008 at 1:24 PM Rating: Good
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I woke up to 8" this morning.

No snow though.
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#32 Mar 04 2008 at 4:45 PM Rating: Decent
The latent heat of fusion of water is about 334 Joules/gram. Assuming 7 inches of snow on a 3 meter by 4 meter driveway, that is about 18 cm x 300 cm x 400 cm = 2x10^6 cm^3 of ice, which has a density of about 1 g/cm^3, so about that many grams. At 334 joules per gram, that is: 7x10^8 joules of energy to melt it. One kilowatt-hour of electric energy costs me currently about US$0.16, and is literally 1000 Watts (1W=1J/s) times 3600 sec(one hour) = 3.6x10^6 Joules. It would cost US$31 to defrost that driveway in the hair blow drier fashion. And that is assuming every joule of energy goes directly into melting snow, none escapes to the air. You might be able to get close (maybe, say, a factor of two more) to that but certainly not with blow driers.

However, I just looked up the density of snow, and it is only 10% of the density of ice, so you can safely divide that figure by 10, so only about US$3.10 to remove 7 inches of snow. But that is just one day's worth (7 inches)! And it assumes 100% efficiency. Lastly, it neglects the energy required to take the thermal trip up from whatever temperature it started at to the melting point of ice, but this is likely vastly smaller unless you live in the arctic.
#33 Mar 04 2008 at 4:46 PM Rating: Good
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yossarian wrote:
The latent heat of fusion of water is about 334 Joules/gram. Assuming 7 inches of snow on a 3 meter by 4 meter driveway, that is about 18 cm x 300 cm x 400 cm = 2x10^6 cm^3 of ice, which has a density of about 1 g/cm^3, so about that many grams. At 334 joules per gram, that is: 7x10^8 joules of energy to melt it. One kilowatt-hour of electric energy costs me currently about US$0.16, and is literally 1000 Watts (1W=1J/s) times 3600 sec(one hour) = 3.6x10^6 Joules. It would cost US$31 to defrost that driveway in the hair blow drier fashion. And that is assuming every joule of energy goes directly into melting snow, none escapes to the air. You might be able to get close (maybe, say, a factor of two more) to that but certainly not with blow driers.

However, I just looked up the density of snow, and it is only 10% of the density of ice, so you can safely divide that figure by 10, so only about US$3.10 to remove 7 inches of snow. But that is just one day's worth (7 inches)! And it assumes 100% efficiency. Lastly, it neglects the energy required to take the thermal trip up from whatever temperature it started at to the melting point of ice, but this is likely vastly smaller unless you live in the arctic.
Fair enough.

But I managed to turn this into a knob joke
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