Jawbox wrote:
Whatever the wishes of the KKK, black is not the same as invisible. That other dude is right: Black is the absence of coloUr (really the absorption of all visible wavelengths of light), and for an object to be made invisible it would have to be made utterly transparent, not black.
But in this case it seems like the visible wavelengths of light are in fact being reflected from objects, but then somehow being "erased" by the reversal of the light via this "superlens."
The key is that this superlens is a non-natural metamaterial with very unique properties. From what I've gathered, another version of the refractive index (n) is the square of a material's relative permittivity times it's relative permeability. The "relative" part is, I think, relative to the light's velocity. So n shows the extent to which the velocity of light is slowed as it passes through a given material.
Now, certain metameterials are engineered such that both the relative permeability and the relative permittivity are negative. I'm not going to pretend I know exactly what that means or how it's accomplished, but it nevertheless appears to be true and undisputed.
So by taking the negative square root of the product of these two variables, you obtain a negative n for this metamaterial. This means that it has the curious property of creating transparency as far as the given wavelengths of light in question. Weird.
Light, when it contacts a particle, is absorbed then remitted. This process slows its progression through a material, varient on the types of particles on it and the density in which those particles are packed. Though it's often overlooked, this also varies with temperature, intensity, and wavelength. Furthermore, this isn't just light, but electromagnetic radition over a varient spectrum.
The
index of refraction we've been debating is the rate at which light progresses through a material. As I gave above, (n = c / v), where n is the index, c is the speed of electromagnetic radiation in a vacuum, and v is the speed of the particular representative of electromagnetic radiation in the particular medium. The information you gave above was a good summary of a way of determining it.
As for causing a black color in a material, this is because of destructive interference. Electromagnetic waves can be seen as, well, just that: waves. Waves, when they encounter one another in space, become
superimposed. If the waves are equal and opposite with the appropiate phase difference, then their superimposition results a set zero waves, effectively destroying both waves.
One interesting experiment is to take a light source, then a sheet with two thin slits in close proximity (thin being about 1/16 mm, and close being within the same distance). Take a look at the projected light, and you'll notice "bands" of light where parts are brighter, and then dark, and then bright again, and so on. The areas of brighter light are from constructive interference, where the light waves, superimposed, added up to create a greater intensity. The areas of darkness are areas of destructive intereference, where the waves have, in effect, cancelled one another out (the two waves being those from the two slits).